Finding the path between two points

3 次查看（过去 30 天）
Zena Assaad
Zena Assaad 2015-7-2
评论： Zena Assaad 2015-7-6
Hi all,
I have two x y z coordinates and I need the path between these two points. It does not necessarily need to be the shortest distance path. I am working with a (3x30) position matrix. The first row represents x, the second row is y and the third row is z.
Point 1: (x1,y1,z1)
Point 30: (x30,y30,z30)
Position matrix: [x1 .......... x30
y1 .......... y30
z1 .......... z30]
Point 1 and point 30 are given. I need something simple that will give me the remaining 28 points within the matrix.
Thanks in advance!
  2 个评论
James Tursa
James Tursa 2015-7-2
编辑：James Tursa 2015-7-2
Any restrictions on the path? E.g., is a diagonal jump (two indexes changing at the same time) OK? Can indexes only change a max of 1 for each point?
Zena Assaad
Zena Assaad 2015-7-2
No, there are no restrictions on the path.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

James Tursa
James Tursa 2015-7-2
编辑：James Tursa 2015-7-2
E.g., a somewhat "linear" path allowing "diagonal" jumps (more than one index can change at a time):
Point1 = whatever;
Point30 = whatever;
Pmatrix = [round(linspace(Point1(1),Point30(1),30));
round(linspace(Point1(2),Point30(2),30));
round(linspace(Point1(3),Point30(3),30))];
If the points do not need to be integers, then skip the rounding.
  7 个评论
显示 5更早的评论
James Tursa
James Tursa 2015-7-2
编辑：James Tursa 2015-7-2
They are not zero ... they are just displaying as zero because of the display format you are using (probably short) and the wide range of values in the result. Try this:
format long g
Then display the result again.
Or just look at the last row by itself:
Pmatrix(3,:)
Zena Assaad
Zena Assaad 2015-7-6
That worked perfectly. Thank you very much for all your help.

请先登录，再进行评论。

更多回答（1 个）

Image Analyst
Image Analyst 2015-7-2

类别

在 Help Center 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by