Access the array index using find
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Hello ,
I have an array A1 = [1 12 23 45]; and
second array A1_1 = [45 23];
I need to find the index of 45 and 23 in first array A1. I am using following function to do this find(a==a_1(1)) --Output =4 find(a==a_1(2)) --Output =3 I want to get this for multiple elements of array .
It would be grateful if you let me know the changes that are to be done to get it for multiple elements in an array.
Looking forward to hear from you at the earliest.
Thanks Pankaja
采纳的回答
Azzi Abdelmalek
2015-7-2
编辑：Azzi Abdelmalek
2015-7-2
a= [1 12 23 45];
b= [45 23]
out=arrayfun(@(x) find(a==x),b,'un',0)
Or using a for loop. The previous answer, also uses a loop.
for k=1:numel(b)
out{k}=find(a==b(k));
end
更多回答（1 个）
Titus Edelhofer
2015-7-2
Hi,
I guess you are looking for this:
A1 = [1 12 23 45];
A1_1 = [45 23];
[~,idx] = ismember(A1_1, A1)
idx =
4 3
Titus
2 个评论
Azzi Abdelmalek
2015-7-2
What if A1 = [1 12 45 23 45]?
Titus Edelhofer
2015-7-2
Yes, you are right. In this case you would find only the first of the two 45 ...
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