how to stop simulation when enter in a infinite loop
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hi
how i deal in a situation where by mistake infinite loop initiate or where i want to see step by step response of any program or loop. kindly help me
regards
1 个评论
B.k Sumedha
2015-7-4
编辑：B.k Sumedha
2015-7-4
U can use debug option or else use breakpoints.
采纳的回答
Geoff Hayes
2015-7-4
Mudasir - sometimes, if I have written some code that makes use of a while loop, I will include a maximum iteration counter to prevent the code from getting stuck in that loop. For example, if the while loop looks something like
while someCondition
% do something
end
then I would change this to
MAX_ITERATIONS = 1000;
iterCount = 0;
while someCondition && iterCount <= MAX_ITERATIONS
% do something
iterCount = iterCount + 1;
end
if iterCount > MAX_ITERATIONS
fprintf('exited loop perhaps because max iteration count reached\n');
end
5 个评论
Mudasir Ahmed
2015-7-4
Image Analyst
2015-7-4
Using a failsafe like Geoff suggested is an excellent idea . I always do it and in fact, consider it an essential idea. I suggest you permanently adopt this essential programming concept. With my code, which needs to be super robust and validated, about half of the lines of code are taken up with comments, fail-safes, input validations, error checking, error logging, bulletproofing/foolproofing/idiotproofing, try/catch, attempted repair of bad inputs (workarounds), etc.
Mudasir Ahmed
2015-7-4
编辑：Mudasir Ahmed
2015-7-4
Geoff Hayes
2015-7-4
Mudsair - fitness must have more than one row. Note that fitness(:,1) will return a column vector of ones and zeros and so it is this column that is causing a problem with the conditional operator. What does the condition
fitness(:,1) > 2
mean to you? Are you checking to see if all elements in the first column are greater than 2? Or, is this condition considered true (by you) if at least one element in the first column is greater than 2?
all(fitness(:,1)>2)
to return a single logical value (0 or 1). If the latter, then use any to determine if at least one value in your column is non-zero (i.e. one) as
any(fitness(:,1)>2)
Try the option that best suits your needs.
Mudasir Ahmed
2015-7-4
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