condition for including difference between nan

2015 7 5
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更新时间：2015 7 6
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Hi Guys, I had the following line for a condition I needed.
if (abs((tempBeforeDelam(i,j,1)-tempBeforeDelam(i,j,2)))< 1 ...
&& abs((tempBeforeDelam(i,j,2)-tempBeforeDelam(i,j,3))) < 1 ...
&& abs((tempBeforeDelam(i,j,3)-tempBeforeDelam(i,j,4))) < 1 ...
&& abs((tempBeforeDelam(i,j,4)-tempBeforeDelam(i,j,5))) < 1 ...
&& abs((tempBeforeDelam(i,j,5)-tempBeforeDelam(i,j,1))) < 1)
and replaced it with
if all( abs( diff([ squeeze(tempBeforeDelam(i,j,:)); tempBeforeDelam(i,j,1) ]) ) < 1)
now I also need to incorporate a condition that says that even if the difference is nan proceed to the next step.
Any help would be appreciated.
Thanks

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Guillaume
Guillaume 2015-7-6
编辑：Guillaume 2015-7-6

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somediff = diff([squeeze(tempBeforeDelam(i,j,:)); tempBeforeDelam(i,j,1)]);
if all(abs(somediff) < 1 | isnan(somediff))
%do it
end
The only way of returning true in a comparision expression that contains NaN is to explicitly test it with isnan. NaN is never smaller than, greater than or equal to any number (or another NaN).

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