*Problem Find area surface*

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justin Taylor
justin Taylor 2011-12-4
x = ( 1-u )(3+cos v)cos(2pi*u)
y = ( 1-u )(3+cos v)sin(2pi*u)
z = 4u + ( 1-u )sinv.
D={(u,v)|0<=u<=1,0<=v<=2pi}
http://i1203.photobucket.com/albums/bb396/kidstar079/Capture-1.png
mycode
{ syms u v;
x = (1-u).*(3+cos(v)).*cos(pi*u);
y = (1-u).*(3+cos(v)).*sin(pi*u);
z = 8*u+( 1-u ).*sin(v);
F=[x,y,z];
ru=diff(F,[u]);
rv=diff(F,[v]);
ruv=ru.*rv;
druv=sqrt(ruv(1).^2+ruv(2).^2+ruv(3).^2);
S=int(int(druv,u,0,1),v,0,2*pi)
}
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Jan
Jan 2011-12-5
Please, Anh Em, stop sending me emails. This is a public forum and it lives on the idea that all information are shared.
Whenever I know an answer, I take the time to post it here. Therefore there is no reason to push me by emails. In opposite: it is annoying, and therefore a bad idea, if you want to get an answer.
As Walter I suggest to read: http://www.mathworks.com/matlabcentral/answers/6200-tutorial-how-to-ask-a-question-on-answers-and-get-a-fast-answer and
http://www.mathworks.com/matlabcentral/answers/8626-how-do-i-get-help-on-homework-questions-on-matlab-answers

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Walter Roberson
Walter Roberson 2011-12-4
This is a curved horn that is not self intersecting. You can drop the z coordinate and simply integrate the circumference of the circle with radius (1-u)*(3+cos(v)) over your u, v.
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justin Taylor
justin Taylor 2011-12-12
Can you solotions details it ? I was tried it.
justin Taylor
justin Taylor 2011-12-13
multiplication have direction vector ? i don't known it .

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