how to resolve "Conversion to cell from double is not possible." error

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ram vanguri
ram vanguri 2015-7-17
编辑： ali hamzah 2024-7-17
Can someone point out what I am doing wrong.
a=cell(1,2);
for i=1:2
a{i}=mat2cell(zeros(8,8,2),8,8,2);
a{1}(:,:,1)=randi(8,8);
when i run the above lines i am getting error shown below. error:"Conversion to cell from double is not possible."
how to assign or modify the values in the cell. thanks

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2015-7-17
编辑：Azzi Abdelmalek 2015-7-17
a=cell(1,2);
for i=1:2
a(i)=mat2cell(zeros(8,8,2),8,8,2);
a{i}(:,:,1)=randi(8,8);
end

更多回答（2 个）

Guillaume
Guillaume 2015-7-17
What is the purpose of the call to mat2cell here. mat2cell with the dimension arguments the same size as the matrix just puts the whole matrix into a single cell, so
{zeros(8,8,2} %does exactly the same thing as
mat2cell(zeros(8,8,2),8,8,2) %and is much clearer.
If the intention was indeed to put the matrix into a single cell, then your loop should have been:
for i = 1:2
a{i} = zeros(8,8,2); %or a(i) = {zeros(8,8,2)};
a{i}(:,:,1) = randi(8,8);
end
Or:
for i = 1:2
a{i} = cat(3, randi(8,8), zeros(8,8));
end
Or even simply:
a = mat2cell(cat(3, randi(8,8*2,8), zeros(8*2,8)), ones(1,2)*8, 8, 2)
ali hamzah
ali hamzah 2024-7-17
编辑：ali hamzah 2024-7-17
what the error (Error using Untitled18 (line 12)
Conversion to cell from double is not possible.)
% Ensure all columns except the last one are numeric
for i = 1:(width(data) - 1)
if iscell(data{:, i})
data{:, i} = grp2idx(categorical(data{:, i}));
elseif ischar(data{:, i})
data{:, i} = grp2idx(categorical(data{:, i}));
end
end

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