Adjusting equation based on odd/even row

Question

Sha S 2015-7-17

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/230240-adjusting-equation-based-on-odd-even-row

回答： Eric Pahlke 2015-7-17

Hi,

I have 2 matrices. Matrix A is 104x15 and matrix B is 103x1.

I want to add element one in matrix B to the value in row 1 column 4 in matrix A. Then I want to add element 2 in Matrix B to the value in row 2 column 7 in matrix A. Then I want to add element 3 in matrix B to the value in row 3 column 4 in matrix A. Then I want to add element 4 in matrix B to the value in row 4 column 7 in matrix A....and so on. I want to do this for the first 103 rows (I realize I can't do it for 104 rows because matrix B only goes up until row 103).

I pretty much want to add the odds rows in matrix B to column 4 of all the odd rows in matrix A. And then I want to add the even rows in matrix B to column 7 of all the even rows in matrix A. In the end I want one matrix that is 103x1.

Can someone please help me do this. Thank you!

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Answer 1

Eric Pahlke 2015-7-17

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/230240-adjusting-equation-based-on-odd-even-row#answer_186366

在 MATLAB Online 中打开

A = zeros(104,15);
A(:,4) = 1; % Just to distinguish column 4 from column 7
A(:,7) = 101; % Just to distinguish column 4 from column 7
B = (1:103)'; % Define a 103x1 B matrix
C = zeros(size(B)); % Preallocate the new matrix so that we can use the "end" operator
 % Odd values: 1:2:end means start at element 1, increment by 2, continue to the end of the array
 % Even values: 2:2:end means start at element 2, increment by 2, continue to the end of the array
C(1:2:end) = A(1:2:length(B),4) + B(1:2:end); % Odd
C(2:2:end) = A(2:2:length(B),7) + B(2:2:end); % Even