How to assign proper index within a for loop?

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Ali Y.
Ali Y. 2015-7-18
编辑： Azzi Abdelmalek 2015-7-18
Hi, How can I assign proper index within 'for loops', so that I reach to values of all loops? For example, I have a matrix as following; and I want to divide it to two separate matrices. I know I should have two matrices (TA) with dimension: (r=7,c=3) and (r=5,c=3). But I only get the result of last loop , i.e. TA(end). How should I assign proper index at left hand of assignment to get the result of all loops? In this case, I tried TA (c,r,i), so that each matrix get stored in relative (i.e. i) dimension, but it gives an error message "Assignment has more non-singleton rhs dimensions than non-singleton subscripts". Could someone please help me solve and understand this chronic problem of mine?
Thank you in advance
clear all
clc
A1 = [1;1;1;2;2;2;3;3;3;4;4;4];
A2= [1;1;1;1;1;1;1;2;2;2;2;2];
A3 = (10:10:120); A3 = A3';
A = [A1,A2,A3];
b = min(A2): max(A2);
for i = min(b): max(b)
TA = A((find(A2 == b(i))),:);
[r,c] = size(TA)
TA = A((find(A2 == b(i))),:)
end
  2 个评论
Ali Y.
Ali Y. 2015-7-18
Dear Azzi, thank you for your reply, the error arise when the last line of the loop is written as
TA((r,c,i) = A((find(A2 == b(i))),:)
I need to assign TA an index to get the two matrix, when I recall TA outside of the for loop.

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回答（1 个）

Azzi Abdelmalek
Azzi Abdelmalek 2015-7-18
编辑：Azzi Abdelmalek 2015-7-18
You can't do
TA((r,c,i) = A((find(A2 == b(i))),:)
Because find(A2 == b(i)) will return different sizes. but you can use cell array
TA{i} = A((find(A2 == b(i))),:)
To get your matrices
TA{1}
TA{2}

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