You’re missing a test for convergence. I don’t understand your needing any arguments for your function, since it never uses them. It calculates the series and is entirely self-contained. I would just set ‘n’ arbitrarily high and break out of the loop when it converged.
n = 150;
e=0;
ep = 0; % Previous Value Of ‘e’
for k=0:n
e=e+(1/factorial(k));
if e-ep < 1E-7 % Test For Convergence
break
end
de = e;
end
When I ran it, it required only 11 iterations to converge. (I would use a while loop, but your code works with a high enough value for ‘n’.)
