Piecewise Function Graphing Code Help

1 次查看（过去 30 天）
Jesse Rossman
Jesse Rossman 2015-7-26
评论： dpb 2015-7-27
Hello all, I am trying to graph a piecewise function (shown with code below) and keep getting error saying "Error using piecewise (line 2) Not enough input arguments". I need an explanation as I am still learning MatLab. Thank you!
____________________________________________________________________________________________________________________________________
function y = piecewise(x)
x1 = x(0<=x & x<1);
y(find(0<=x & x<1)) = 2.1592*x1+2;
x2=x(1<=x & x<2);
y(find(1<=x & x<2)) = 1.0105*x2+1.1487;
x3=x(2<=x & x<3);
y(find(2<=x & x<3)) = 2.2635*x3-1.3573;
x4=x(3<=x & x,4);
y(find(3<=x & x,4)) = 3.7079*x4-5.6905;
x5=x(4<=x & x<5);
y(find(4<=x & x<5)) = 5.2649*x5-9.1411;
x6=x(5<=x & x<6);
y(find(5<=x & x<6)) = 6.8970*x6-20.079;
plot(x, y)
axis([-1 7 -25 25])
grid on
  5 个评论
显示 3更早的评论
Jesse Rossman
Jesse Rossman 2015-7-27
Ok. I may just not know what you need exactly because I'm new to Matlab. Here is a screen shot, does this help? Thanks for the help! I appreciate it.
dpb
dpb 2015-7-27
Yep...the line you executed says only "piecewise" but the definition of the function is that it requires a vector x. Hence, quite rightly, Matlab complains that there aren't enough input arguments since zero arguments are fewer than one. :)
It appears that the function could have been written w/o needing an argument since the ranges internally are hardcoded, but that wasn't the way it was chosen to do it. Try
piecewise([0:0.1:6])
or, of course, define a vector and pass it...
x=[0:0.1:6];
piecewise(x)

请先登录，再进行评论。

请先登录，再回答此问题。

回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Get Started with MATLAB 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by