Does MATLAB Coder support 'persistent' variables?

Question

JangHo Cho 2015-7-28

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/231434-does-matlab-coder-support-persistent-variables

评论： JangHo Cho 2015-7-28

Hello again.

I have another problem with MATLAB coder. Here is the code.

Function C_td = make_CA_matrix(C_array, A_array, k, N_h)
N_h : horizon length
global N_horizon
persistent count C_tilde;
if isempty(count)
  count = 0;
else
  count = count + 1;
end
if isempty(C_tilde)
  C_tilde = zeros(4*N_horizon,3);
end
index_Cmat = k - N_h;
C_tilde(1:4,:) = C_array(:,:,index_Cmat);
N_state = size(A_array(:,:,1),2);
A = eye(N_state);
for i = 1 : N_h-1
  index_Amat = k - N_h + i - 1;
  A = A_array(:,:,index_Amat)*A;
  index_Cmat = k - N_h + i;
  C_tilde(i * 4 + 1: i * 4 + 4,:) = C_array(:,:,index_Cmat)*A;
end
C_td = C_tilde(1:N_h * 4, :);
end

When I tried to convert this MATLAB code to C code with MATLAB coder, This Error Message I met.

This assignment writes a 'double' value into a 'int32' type. Code generation does not support changing types through assignment. Check preceding assignments or input type specifications for type mismatches. (C_tilde)

Do you have any Idea to Fix this problem?

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Answer 1

Walter Roberson 2015-7-28

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https://ww2.mathworks.cn/matlabcentral/answers/231434-does-matlab-coder-support-persistent-variables#answer_187434

Yes, it does support persistent. See http://www.mathworks.com/help/coder/ug/defining-and-initializing-persistent-variables.html

Which statement is being identified as having the error? If it is the last statement then try initializing C_td near the beginning.

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JangHo Cho 2015-7-28

Thank you Walter Roberson.

if isempty(C_tilde) C_tilde = zeros(4*N_horizon,3); <--Here is where the error is. end

I don't know why the error occurred. Anyway I'll read the article of the link you gave. Thank you.

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Answer 2

Guillaume 2015-7-28

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https://ww2.mathworks.cn/matlabcentral/answers/231434-does-matlab-coder-support-persistent-variables#answer_187438

编辑：Guillaume 2015-7-28

在 MATLAB Online 中打开

I suspect the error is on this line

C_tilde(1:4,:) = C_array(:,:,index_Cmat);

and that C_array is of class int32. Declare C_tilde of the same type:

C_tilde = zeros(4*N_horizon, 3, 'int32');
%or better, if supported by coder:
C_tilde = zeros(4*N_horizon, 3, 'like', C_array);

This has nothing to do with persistent.

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JangHo Cho 2015-7-28

Thank you, Guillaume.

I tried some things after reading your answer.

First thing I should have to do was to change the type of global variable N_horizon to int32 in MATLAB workspace (Say, N_horizon = int32(5);...) because I register N_horizon as int32 in MATLAB coder.

Next thing I should have to do was to modify the initialization routine of a persistent variable C_tilde.

if isempty(C_tilde) C_tilde = zeros(4*N_horizon,3); end

to if isempty(C_tilde) C_tilde = zeros(40,3); end

Then new problem occurred.

C_td = C_tilde(1:(N_h * 4), :); <<-

The error message was 'Could not determine the size of this expresstion.'

N_h is an input argument of the function make_CA_matrix. (function C_td = make_CA_matrix(C_array, A_array, k, N_h) So the size of C_td should depend on N_h.

Do you have any good idea?

JangHo Cho 2015-7-28

Ah, I've tried one more thing and I think it worked.

When I tried code conversion with MATLAB Coder, I set the 'Enable variable-sizing' to 'No'. But this time I reset the value to default('Yes') and the function was generated successfully. The prototype of the function is like this.

void make_CA_matrix(const double C_array[120], const double A_array[90], int k, int N_h, double C_td_data[], int C_td_size[2])

Thank you for helping a confused dummy. :)

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