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intersection of multiple images

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k.v.swamy
k.v.swamy 2011-12-6
hi chandra, what should i do if i want to display the intersection portion.
  1 个评论
Image Analyst
Image Analyst 2011-12-6
There is no context for this question. You should reply to your other thread and delete this one, or at the very least, put in a link to the other thread that you split off from.

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采纳的回答

Chandra Kurniawan
Chandra Kurniawan 2011-12-6
Hello,
Sorry for waiting.
Here the code :
array = uint8(intersection);
for row = size(intersection,1) : -1 : 1
if ~any(find(intersection(row,:)))
array(row,:) = [];
end
end
for col = size(intersection,2) : -1 : 1
if ~any(find(intersection(:,col)))
array(:,col) = [];
end
end
imshow(array);
  19 个评论
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Chandra Kurniawan
Chandra Kurniawan 2011-12-7
Hi, k
I think it is impossible.
You can only do matrix subtraction if both of dimension and size are same.
If we know about matrix concept, if we have matrix A [p x q] and B [r x s], subtraction matrix A with matrix B can be occur only is p == r and q == s.
So, you cannot perform it with different size of two matrices.
k.v.swamy
k.v.swamy 2011-12-7
yes i do agree with the answer,but in my assignment iam given two sets of images for which i have to find the intersection
https://picasaweb.google.com/103266594409982679463/ImagesSet1?authuser=0&feat=directlink
https://picasaweb.google.com/103266594409982679463/IMAGESSET2?authuser=0&feat=directlink
i hav given u the links and i have written the code like
clc;
clear all;
close all;
I = double(imread('work.jpg'));
J = double(imread('work1.jpg'));
imshow(uint8(I)),figure,imshow(uint8(J))
l=length(I);
for i=1:l
for j=1:l
if i>1200
i=1200
end
if I(i,j)==J(i,j)
s(i,j)=I(i,j);
elseif I(i,j)~=J(i,j)
k(i,j)=I(i,j);
end
end
end
figure,imshow(uint8(k))
pl verify for once

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更多回答（1 个）

Chandra Kurniawan
Chandra Kurniawan 2011-12-7
I got little confused with your question.
Let me pick one picture.
Then which another picture will be intersected with that image??
  3 个评论
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k.v.swamy
k.v.swamy 2011-12-8
chandra if u get any clue pl reply me.
k.v.swamy
k.v.swamy 2011-12-9
hi chandra,can u pl look at my problem and giv me reply.

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