Why is the if statement not working?

Question

tash7827 2015-8-3

0
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https://ww2.mathworks.cn/matlabcentral/answers/232187-why-is-the-if-statement-not-working

回答： the cyclist 2015-8-3

this is my code - it is supposed to be a binary array, where the length of time (through the array) that the "1"s are held is determined by "time" - why is the if statement not working based off of the output of "time"?

function cube=cube(exp)  
exp=zeros(60,96,10);
time=randi([3 7]);
if time==3
   for j=1:size(exp,1);
    for jj=1:size(exp,2);
        rand=randi([1 8]);
        exp(j,jj,rand:rand+2)=1;
    end
   end
elseif time == 4 
    for j=1:size(exp,1);
    for jj=1:size(exp,2);
        rand=randi([1 7]);
        exp(j,jj,rand:rand+3)=1;
    end
    end
elseif time == 5 
    for j=1:s ize(exp,1);
    for jj=1:size(exp,2);
        rand=randi([1 6]);
        exp(j,jj,rand:rand+4)=1;
    end
    end
elseif time == 6 
    for j=1:size(exp,1);
    for jj=1:size(exp,2);
        rand=randi([1 5]);
        exp(j,jj,rand:rand+5)=1;
    end
    end
elseif time == 7 
    for j=1:size(exp,1);
    for jj=1:size(exp,2);
        rand=randi([1 4]);
        exp(j,jj,rand:rand+6)=1;
    end
   end
cube=exp
end

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the cyclist 2015-8-3

One suggestion, aside from trying to solve your main problem, is that you should not be using MATLAB keywords as variable names, because the code may behave in unexpected ways, and also the code simply becomes very confusing (especially for veteran users). In your case, exp and rand should be avoided as variable names.

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