Delete rows at intervals

Hi, I have a very large matrix, and I would like to delete rows at specific intervals.
For example, I have the following matrix : [ 1 2 ; 3 4 ; 5 6 ; 7 8; 9 10; 11 12; 13 14; 15 16 ;17 18; 19 20; 21 22 ; 23 24]
I would like to delete every fourth row so the matrix looks like: [ 1 2; 3 4 ; 5 6; 9 10 ; 11 12; 13 14; 17 18; 19 20; 21 22 ]
Any help would be greatly appreciated.
Thanks,
Seamus

1 个评论

You could select individually which rows you want, like
A = [ 1 2 ; 3 4 ; 5 6 ; 7 8; 9 10; 11 12; 13 14; 15 16 ;17 18; 19 20; 21 22 ; 23 24]
B = A([1:3,5:7,9:11],:)
Of course, for large data this would be impractical, so you can use a for loop for such task combined with mod operator and vertical concatenation
A = [ 1 2 ; 3 4 ; 5 6 ; 7 8; 9 10; 11 12; 13 14; 15 16 ;17 18; 19 20; 21 22 ; 23 24];
B = zeros(0,2);
for i=1:length(A)
if (mod(i,4) ~= 0)
B = vertcat(B,A(i,:));
end
end
In other words, we create an empty 0-by-2 matrix (because A uses 2 cols per row) and then we just push to that matrix each row that we want to. In this case, we push every row that is not a multiple of 4 (using the mod function).

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 采纳的回答

A(4:4:end,:) = [];

3 个评论

Hi Walter, thanks very much for this. I may be incorrect but I think this extracts out every fourth row from the original matrix. In this instance I'm just looking to delete every fourth row, and leave the remainder.
No, extracting every 4th row would be
every4thRow = A(4:4:end,:)
on the right hand side. When you assign [] to an array element, that means to delete the element.
My apologies, I read it wrong. That's perfect, thank you very much.

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