Efficiency help

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Andy
Andy 2011-12-7
Hi, i need some more help with effeciency. This following code is running very slowly (took over 800 seconds for one of my data sets)
for l= 1:listsize;
for m = 1:length(peak_loc2{l});
counter2 =1;
while peak_loc2{l}(m)~= mymatrix2(1, counter2)
counter2=counter2+1;
end
mymatrix2(2,counter2) = mymatrix2(2,counter2) +1;
end
end
here listsize is 271 peak_loc2 is a list of cell, around 100 cells, each containing anywhere from 2 to a few hundred variables
mymatrix2 is a 2X3000s that list all the peaks in peak_loc2, and non-recurring

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Sean de Wolski
Sean de Wolski 2011-12-7
you can replace the while loop with
counter2 = find(mymatrix(1,:)==peak_loc2{1}(m),1,'first')
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Sean de Wolski
Sean de Wolski 2011-12-7
If you have over 3000 variables there's something we're not seeing. Perhaps you could post a sample matrix (small) or a *.mat file to somewhere.
Andy
Andy 2011-12-7
it turns out it still graphs it properly the way i wanted, so its fine thanks

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