I will appreciate any suggestion on this simple code. I want to substitute the elements of x >5 with 6 and x<5 with zero.
显示 更早的评论
for j=1:1:8
x=[1 2 3 4 5 6 7 8];
if x(j)>5
x(j)=subs(x(j),x(j),6);
else
x(j)=subs(x(j),x(j),0);
end
end
采纳的回答
Azzi Abdelmalek
2015-8-15
idx=x>5
x(idx)=6
x(~idx)=0
4 个评论
Isaac
2015-8-15
Isaac
2015-8-15
Isaac
2015-8-15
Steven Lord
2015-8-16
Don't define x inside your loop. It's unnecessary and is just going to waste time.
Don't use a loop; vectorize your code as Azzi suggested.
&& is intended to short-circuit when the two criteria you're trying to AND together evaluate to a scalar value. In this case, your criteria do not evaluate to scalar values. In that case, use & to perform elementwise AND.
更多回答（1 个）
matico
2015-8-16
Also:
x=[1 2 3 4 5 6 7 8];
x(x>5) = 6;
x(x<=5) = 0;
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