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I will appreciate any suggestion on this simple code. I want to substitute the elements of x >5 with 6 and x<5 with zero.

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Isaac
Isaac 2015-8-15
回答： matico 2015-8-16
for j=1:1:8
x=[1 2 3 4 5 6 7 8];
if x(j)>5
x(j)=subs(x(j),x(j),6);
else
x(j)=subs(x(j),x(j),0);
end
end

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2015-8-15
idx=x>5
x(idx)=6
x(~idx)=0
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Isaac
Isaac 2015-8-15
In the event when I have two conditions to satisfy, please assist:
for j=1:1:8 x=[1 2 3 4 5 6 7 8]; y(j)=x(j).^2; idx=(x>pi&&x<7); idy=y<2; y(idy)=0; y(idx)=90; end
Steven Lord
Steven Lord 2015-8-16
Don't define x inside your loop. It's unnecessary and is just going to waste time.
Don't use a loop; vectorize your code as Azzi suggested.
&& is intended to short-circuit when the two criteria you're trying to AND together evaluate to a scalar value. In this case, your criteria do not evaluate to scalar values. In that case, use & to perform elementwise AND.

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更多回答（1 个）

matico
matico 2015-8-16
Also:
x=[1 2 3 4 5 6 7 8];
x(x>5) = 6;
x(x<=5) = 0;

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