i not able to find error..not getting right plot

1 次查看(过去 30 天)
clc;
clear all;
k=1;
g=0.01:.1:6;
lambda=2;
b=2;
c=1;
l=2;
for x=0.01:.1:6
T=[];
P=(0.5*lambda)/((b^(lambda*c))*gamma(c));
Q=(k^0.5)*l^(lambda*c-0.5)/((2*pi)^(0.5*(l+k)-1));
R=evalin(symengine, sprintf('meijerG([[1],[]], [[1,0.5],[]],%f)',x^2));
T=[T P*Q*R];
end
plot(g,T)

采纳的回答

dpb
dpb 2015-8-17
for x=0.01:.1:6
T=[];
...
T=[T P*Q*R];
end
plot(g,T)
You wipe out T every pass thru the loop so the result is simply the last P*Q*R computed. Move that outside the loop altho "growing" an array like this dynamically is not good practice; use preallocation and fill instead.
T=zeros(size(0.01:0.1:6)); % preallocate
ix=0; % array index
for x=0.01:0.1:6
...
ix=ix+1;
T(ix)=P*Q*R;
end
Or, use the loop for an integer variable and compute x dynamically as x=x+dx;
  4 个评论
dpb
dpb 2015-8-18
In that case, you've got to allocated a square array instead of a vector and store into it...
T(ix,:)=P*Q*R;

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

尚未输入任何标签。

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by