Expression (equation)
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Hello, how to define an expression, for example 1-e^(-At) where I can define and change parameters A and t and than figure changes of the curve in a graph.
Thanks
采纳的回答
Paulo Silva
2011-12-8
Simplest version I can think of
t=0:0.1:100; % Time vector
A=0.1; % Value of A that you can change
plot(t,1-exp(-A(n)*t)) % Represent it on a figure
If you place the cursor on the value of A you can try several values using the Editor tools (look on the tools of your editor window - 1.0 + ... press those symbols and the script runs with a new value for A)
Just for fun here's a version using subplots
clf
t=0:0.1:10;
A=[0.01 0.1 0 1];
for n=1:4
subplot(2,2,n)
plot(t,1-exp(-A(n)*t))
title(['A=' num2str(A(n))])
end
9 个评论
Jan
2011-12-8
Jan
2011-12-8
Sean de Wolski
2011-12-8
It's the loop iterator that changes the value of A in each subplot in the bottom example. I it's a copy/paste error in the top (example)
Jan
2011-12-8
Paulo Silva
2011-12-8
Yes it is possible and simple, just play with the blocks, t is a Ramp and A is a Constant Source
Paulo Silva
2011-12-8
It took me about 2 minutes to do it, here's a few tips:
1- Start from the parenthesis expression A*t
2- To turn something negative just use a Gain block with value -1
3- Use the Math Function block for the exponential
Jan
2011-12-8
Paulo Silva
2011-12-8
It's just basic math, you use the Product block with inputs A and t and connect that block output to the Math Function block
Jan
2011-12-8
更多回答（1 个）
Sean de Wolski
2011-12-8
And to add on to Paulo's example:
t=0:0.1:100; % Time vector
A=0.1;
y = 1-exp(-A*t); % Value of A that you can change
H = figure;
plot(t,y)
linkdata(H,'on');
shg;
pause(2) %watch the magic in 2 seconds
A = .8;
y = 1-exp(-A*t);
if you want it to automagically update when you change A or y.
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