How can i build a symmetric matrix from a vector ?
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assume i have a 1*n vector like x = [1 2 3 4 5 6], i want to reshape this vector to a symmetric matrix like
symx = [1 2 3; 2 4 5; 3 5 6];
or something like this:
symx = [1 4 6; 4 2 5; 6 5 3];
Thanks for your help
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John D'Errico
2015-8-21
Sorry, but unless you give the rules by which you have chosen to call that a "reshape" where you take 6 numbers and somehow magically decide to reshape them into a 9 element array, then nobody can help you. The mind reading toolbox is still in beta test.
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Moe Money
2017-6-12
I used the functions SQUAREFORM and DIAG
Example: Imagine you want to create a symmetric 4x4 matrix. You need a vector with 10 elements.
>> n=4;
>> vec=[1:10]';
>> sqmat = diag(vec(1:n)) + squareform(vec(n+1:end))
sqmat =
1 5 6 7
5 2 8 9
6 8 3 10
7 9 10 4
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Steven Lord
2015-8-21
The SQUAREFORM function from Statistics and Machine Learning Toolbox gets close, but it puts zeros on the diagonal and fills in the upper and lower triangles, which is not quite what you're asking for but is close. In order to do what you're asking, you can use logical indexing.
x = 1:6;
y = zeros(3);
upperTriangleIndices = triu(true(3));
y(upperTriangleIndices) = x; % Fill in the upper piece
y = y + y.' - diag(diag(y)) % Mirror the upper piece to the lower, which doubles the diagonal
% so subtract off the diagonal
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Moe Money
2017-6-12
Steven: I had a similar question and the function SQUAREFORM solved my problem. Thanks a lot!
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