FOR Loop
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Let us say I have a row vector with "n" number of rows.
e.g. [0 27 29 45 66]';
How can I write a command using a FOR loop, that adds the first element with the second element, then the second element with the third element and so on until it gets to the "n" number of rows.
And in the end adding up all those answers.
So like: (0+27)+(27+29)+(29+45)... and so on.
I'm only a beginner in MatLab and spent hours trying to figure this out. Hope you guys can help. Thanks for the help in advance. :D
采纳的回答
Andrei Bobrov
2011-12-12
aout = 0;
for i1 = 1:numel(a)-1;
aout = aout + a(i1) + a(i1+1);
end
without loop for..end
n = numel(a)
aout = sum(a(1:n-1)+a(2:n))
3 个评论
Walter Roberson
2011-12-12
sum(a(1:n-1)+a(2:n)) can also be expressed as
a(1) + 2*sum(a(2:n-1)) + a(n)
Mayu
2011-12-12
Sean de Wolski
2011-12-12
aout(end)
更多回答（2 个）
Shouvik Das
2011-12-12
Considering you need to store each intermediate output in another array. Let input array with n rows be inputArray
outputArray=[];
for i=1:length(inputArray)-1
outputArray(i)=inputArray(i) + inputArray(i+1);
end
Hope this helps.
Regards Shouvik
Anurag Pratap Singh
2020-6-25
编辑：DGM
2023-3-4
Hi Mayu
You could use an extra array for storing every output let say addArr array and then add each elements of the addArr.
addArr = [];
for i = 1:length(inputArr)
addArr(i) = inputArr(i)+inputArr(i+1);
end
Then add each element of addArr
result = 0;
for i = 1:length(addArr)
result = result+addArr(i);
end
The result variable has the cummulative sum of all the elements in input array.
Thank you
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