Accessing Matrix Rows using Logical Indexing
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This is probably a very simple question to answer, and I'm sure its been asked a million times, but I just can't seem to find an answer that works for me.
Let's say I have an array like this:
A = [1 1 1 1;2 2 2 2;3 3 3 3;4 4 4 4];
A =
1 1 1 1
2 2 2 2
3 3 3 3
4 4 4 4
Now, I want to somehow return all the rows where the values in the second column are greater than 3.
I know I can get the logical indices like this:
B = A(:, 2) > 2;
B =
0
0
1
1
Now, if I then do this:
C = A(B);
C =
3
4
What I get back is a vector that contains the values from the first column who's rows correspond to the indices from B that are 1.
What I want instead though, is all four columns instead of just the first column.
C =
3 3 3 3
4 4 4 4
So far, the only way I know of to get this to work, is to use a for loop, like this:
counter = 1;
for i = 1:size(A, 1)
if (A(i, 2)) > 2
C(counter, :) = A(i, :);
counter = counter + 1;
end
end
This is kinda inefficient though, since it needs to loop through every element instead of using MATLAB's powerful array processing features.
Can someone tell me how to accomplish what I'm trying to, without using loops?
Thanks!
采纳的回答
Matt Fig
2011-3-2
A = [1 1 1 1;2 2 2 2;3 3 3 3;4 4 4 4];
B = A(:, 2) > 2;
C = A(B,:);
Or for short:
C = A(A(:, 2) > 2,:);
4 个评论
Kiran Ramaswamy
2011-3-2
Rizwan Khan
2020-7-29
id = A(:,2)>2;
A = A(id,:);
Its simply the concept of logical indexing.
Try to use the concept of logical indexing and vectorization wherever possible to avoid the computational loops.
Paul Safier
2022-2-2
Javier Cabello
2022-5-16
That's so cool! I didn't know you could use logical indexing as a reference to matrix positions. Where can I read more of this?
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