how the function typecast works when convert double to uint8

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Yucheng Fu
Yucheng Fu 2015-8-31
评论： Yucheng Fu 2015-9-2
I test the function typecast as follows:
z=double(1);
z1=typecast(z,'uint8');
and the results shows the
z1 = 0 0 0 0 0 0 240 63
As to my knowledge, each element in z1 should represent one 8-bit unsigned number. But the sum is not equal to 1.
Does anyone know how the function works and what's the meaning in vector z1?

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Cedric
Cedric 2015-8-31
编辑：Cedric 2015-8-31
Look at the difference between CAST and TYPECAST, and you will understand what happens in your example.
PS: if you want to understand where these 240(F0) and 63(3F) come from, have a look a this wiki.
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Yucheng Fu
Yucheng Fu 2015-9-2
Thank you for the help. The double format has 64 bit length. This explains exactly what happens to my case. When the typecast convert it to uint8, it should have 8 separate numbers.

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