Repetition of rows of a matrix maintaining the number of columns

1 次查看(过去 30 天)
Hi all.
I also want to create a new matrix from a previous one (A) such all the elements in the first row are copied with N replications and the same should be done for the next row till I reach last row.
The order of new matrix is also N * [rows(A)*cols(A)]; but in my case its number of rows has to be N*rows(A) and the number of columns has to be the same as the previous (A) matrix.
For example, imagine my A matrix is A=[ 1 2
3 4
5 6]
If I replicate N=2 all the rows, my new A_ matrix should be A_=[1 2
1 2
3 4
3 4
5 6
5 6]
Can you help me, please?
Thanks and regards
  1 个评论
Sean de Wolski
Sean de Wolski 2011-12-13
+1 Well written question with sample data, operation, result and proof you searched the records (a rarity)!

请先登录,再进行评论。

回答(1 个)

Paulo Silva
Paulo Silva 2011-12-13
A=[ 1 2
3 4
5 6]
N=1; %number of repeats
kron(A,ones(N+1,1))
  1 个评论
Sean de Wolski
Sean de Wolski 2011-12-13
+1`But I'd recommend for readability purpose keeping N to be the number of repeats as a multiplicative number, i.e. 1 repeat = what you have, two repeats = Ivan's example etc.

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 MATLAB 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by