i am trying to execute the problem code but i am getting error in this line "Linedata(n1+k,:)=Candidate(sw1(k),:);"
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i am trying to execute this problem code but i am getting error in it.
function f=bench_func(x)
  [ps,d]=size(x);
  %Transmission Network Expansion Planning 
  % Maximum and minimum bound of the population that to be generated is 1 and 16.  
      sw=ceil(x);
      data6Bus;
      n1=length(Linedata(:,1));
      sw1=sw;
      for k=1:length(sw1)
          Linedata(n1+k,:)=Candidate(sw1(k),:);
      end
      n_orginalLine=n1;
      n=length(Pgen);
      B=zeros(n,n);
      Nline=length(Linedata(:,1));
      %Ncand=max(Candidate(:,1));
      Xline=Linedata(:,4);
      pijmax=Linedata(:,6);
      Tap=ones(n);
      for C=1:Nline
          bline(C)=1/Xline(C);
          k=Linedata(C,2);
          m=Linedata(C,3);
          B(k,m)=B(k,m)-(bline(C));
          B(m,k)=B(k,m);
          B(k,k)=B(k,k)+(bline(C));
          B(m,m)=B(m,m)+(bline(C));
      end    
  B(1,1)=10000000;
  X=inv(B);
  delP= Pgen-Pload;
  delP=(delP');
    delta=X*(delP);
    pij=zeros(Nline,1);
    for k=1:Nline
        i=Linedata(k,2);
        j=Linedata(k,3);
        pij(k)=(delta(i)-delta(j))/Xline(k);
    end
    PIPbase=0.0;
    f=sum(Linedata(n_orginalLine+1:end,7))+30;
    pen=0;
    for i=1:length(Linedata(:,1))
        pen=pen+5000*max((abs(pij(i))-Linedata(i,6)),0);
    end
    for i=1:length(Candidate(:,1))
        [a ]=find(sw==i);
        if length(a)>3
            pen=pen+1000;
        end
    end
    f=f+pen;
error
Error in bench_func (line 112)
        Linedata(n1+k,:)=Candidate(sw1(k),:);
please help me to solve this code
4 个评论
  Brendan Hamm
    
 2015-9-2
				So, one of the elements of sw1 has the value of -5, implying that x must have had a negative value such that ceil(x) == -5. Either this should be an invalid input to x or you are indexing in an unanticipated manner.
  Walter Roberson
      
      
 2015-9-2
				Or data6Bus is altering sw .
I make it a policy never to read minds after having been up all night, so we are going to need the source of data6Bus this time. And we are going to need to know max(x) and min(x)
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