Function will accept scalars but not vectors.

Question

Josh McCraney 2015-9-5

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/239904-function-will-accept-scalars-but-not-vectors

编辑： per isakson 2015-9-5

I have a question that I have not been able to find. The below function accepts outside scalar inputs but not vectors. The code is below.

Also, a, b, delta,FA,Hi,vHnew,iv are all scalars defined outside the function. The vector I would like to add as an input is x, which I've commented below what it could be. However, even if I add this to the function line and fa, fb, and fc, along with the fx function at the end, I still receive "Error Not enough input arguments." Please help me so this function can operate on x when it is defined outside the function. Any help is greatly appreciated!

    function c = mshvol(a, b, delta,FA,Hi,vHnew,iv)
    fa = f(a,FA,Hi,vHnew,iv);
    fb = f(b,FA,Hi,vHnew,iv);
    while ( abs(b - a) > 2*delta )
     c = (b + a)/2;
     fc = f(c,FA,Hi,vHnew,iv);
     if sign(fc) ~= sign(fb)
     a = c;   fa = fc;
   else
    b = c;  fb = fc;
    end% end if
   end% end while
  function fx = f(zbulk,FA,Hi,vHnew,iv,x)
  dx=.001;
%     x=0:dx:5;
    y=25-x.^2;
    diff = abs(x-zbulk);
    [~, idx] = min(diff); %index of closest value
    z=y(idx:end);
  fx = zbulk*15+trapz(z)*dx-70;  %%Volume balance
  return;

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per isakson 2015-9-5

编辑：per isakson 2015-9-5

在 MATLAB Online 中打开

Try

>> c = mshvol( 1, 2, 0.01,3,4,5,6,7)
c =
    1.0156

and

>> c = mshvol( 1, 2, 0.01,3,4,5,6,[0:0.001:5])
c =
    1.4219

where

function c = mshvol(a, b, delta,FA,Hi,vHnew,iv,x)
    fa = f(a,FA,Hi,vHnew,iv,x);
    fb = f(b,FA,Hi,vHnew,iv,x);
    while ( abs(b - a) > 2*delta )
        c = (b + a)/2;
        fc = f(c,FA,Hi,vHnew,iv,x);
        if sign(fc) ~= sign(fb)
            a = c;   fa = fc;
        else
            b = c;  fb = fc;
        end% end if
    end% end while
end
function fx = f(zbulk,FA,Hi,vHnew,iv,x)
    dx=.001;
    %     x=0:dx:5;
    y=25-x.^2;
    diff = abs(x-zbulk);
    [~, idx] = min(diff); %index of closest value
    z=y(idx:end);
    fx = zbulk*15+trapz(z)*dx-70;  %%Volume balance
end

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Answer 1

Star Strider 2015-9-5

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/239904-function-will-accept-scalars-but-not-vectors#answer_191406

I’m not quite sure what you’re doing, and we don’t have your ‘f’ function. The solution is likely to vectorise your code. See Array vs. Matrix Operations for details.

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Josh McCraney 2015-9-5

Thanks for replying! To clarify, on the lines of code where I have fa = f(a,FA,Hi,vHnew,iv) I have changed to fa = f(a,FA,Hi,vHnew,iv,x), where I included the x. This was necessary for the scalar values a,FA,Hi,vHnew,iv. However, this still does not work.

Does this clarify the issue?