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counting column bits with the same weight in binary array

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Henry Buck
Henry Buck 2015-9-7
评论： Henry Buck 2015-9-9
I have a binary array and I want to count the column with the same weight.
I want to do it with function...m-file
I hope that someone can help me to solve it.
Thanks Henry
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Henry Buck
Henry Buck 2015-9-8
编辑：dpb 2015-9-8
For example:
19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0
0 0 0 0 1 0 0 0 0 0 0 0 0 1 1 0 1 1 0 0
0 1 0 0 0 1 0 0 0 1 1 0 1 0 1 0 1 1 0 1
1 0 1 0 0 0 1 0 0 0 1 1 1 0 1 0 0 0 1 1
0 0 1 0 0 1 0 1 0 1 0 0 0 1 0 0 1 0 1 1
1 1 0 0 1 0 0 0 1 0 1 1 1 1 0 0 0 0 0 1
0 1 1 1 1 1 0 0 1 0 0 0 0 0 0 1 0 0 0 0
0 0 1 1 1 1 1 1 0 1 0 0 0 0 0 1 1 1 1 0
There is 6 col with the same weight (two 1 bits) - col=0,3,6,7,11,15.
There is 8 col with the same weight (three 1 bits) - col=1,9,10,12,13,14,17,18.
There is 5 col with the same weight (four 1 bits) - col=2,4,5,16,19.
dpb
dpb 2015-9-8
>> [0:size(a,2)-1;sum(a)]
ans =
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19
2 3 4 2 4 4 2 2 2 3 3 2 3 3 3 2 4 3 3 4
>>
So, turns out not as far off as thought if you count from the left rather than using the header row as the column number. Other than missing one '2' (col 8), seems ok...

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dpb
dpb 2015-9-7
编辑：dpb 2015-9-8
n=hist(sum(array),0:size(a,1));
N th element of n will contain counts for that number of bits from zero to size(array,1); ie, for all possible totals from no bits set to all.
ADDENDUM
>> [0:size(a,1);hist(sum(a),0:size(a,1))]
ans =
0 1 2 3 4 5 6 7
0 0 7 8 5 0 0 0
>> sum(ans(2,:))==size(a,2) % sanity check...
ans =
1
>>
Total number does equal number of columns in array...
Actually, there are 7,8,5 of wt=2,3,4, respectively.
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dpb
dpb 2015-9-8
If it's a subset of rows, only the array indices to refer to the subset...
r1=3; r2=6;
n=hist(sum(array(r1:r2,:)),0:size(a,1));

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