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Elegant way of "sending to the next row" in a matrix

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Matt
Matt 2015-9-10
编辑： Stephen23 2015-9-10
Hello,
I have a 1x36 matrix that I want to cut in bits. In my specific case I want to obtain a 6x6 matrix from this 1x36 matrix. Every 6 column of the original 1x36 matrix I want to go to a next row.
How can I do this in an elegant way?
Thanks!

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Anthony Poulin
Anthony Poulin 2015-9-10
I have not the same result and using a transpose I think that I get what you want.
A=1:10;
B=reshape(A, [5,2])'
So, B =
1 2 3 4 5
6 7 8 9 10
  1 个评论
Stephen23
Stephen23 2015-9-10
编辑：Stephen23 2015-9-10
Note that you should use the non-conjugate transpose .' rather than a simple '.
In fact it is a good habit to always use the non-conjugate transpose unless you specifically need the complex conjugate.

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更多回答（1 个）

Anthony Poulin
Anthony Poulin 2015-9-10
Hello,
Do you try to use the "reshape" function?
  2 个评论
Matt
Matt 2015-9-10
Yes, but it doesn't give me what I want. For example if I have the following matrix (as per Matlab example):
A = 1:10;
If I reshape it with this command:
B = reshape(A,[5,2]);
It will give me:
1 3 5 7 9
2 4 6 8 10
But what I want is:
1 2 3 4 5
6 7 8 9 10
Hamoon
Hamoon 2015-9-10
编辑：Hamoon 2015-9-10
B=reshape(A,[5,2])
means B will be a (5*2) matrix, you're doing something wrong Matt, just clear your workspace variables and try again. as Anthony said you'll get the result you want using:
A=1:10;
B=reshape(A,[5,2]);
C=B';
C is what you want, and B is a (5*2) matrix
B =
1 6
2 7
3 8
4 9
5 10
C =
1 2 3 4 5
6 7 8 9 10

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