0 个投票

Suppose I have a function
f=inline('x^3+2');
x1=2; x2=-2; x3=4;
Fmin=min(f(x1),f(x2),f(x3))
Now I want to find the value of x (i.e x1 or x2 or x3) corresponding to Fmin Xmin=value of x corresponding to Fmin How to do this??

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Star Strider
Star Strider 2015-9-11

0 个投票

You have to make vectors out of them, then it works:
f = @(x) x.^3+2; % Changed ‘inline’ To Anonymous Function
x1=2; x2=-2; x3=4;
[Fmin,ix] = min([f(x1),f(x2),f(x3)]); % Vector Of ‘f(x)’
x = [x1 x2 x3]; % Vector Of ‘x’
xFmin = x(ix) % ‘argmin’

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