Write a MATLAB program to sketch the following discrete-time signals in the time range of –10 ≤ n ≤ 10. Please label all the graph axes clearly. If the sequence is complex, plot the magnitude and angle separately. i) x(n) = u(n) – u(n – 3)

Question

Superman 2015-9-15

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/243037-write-a-matlab-program-to-sketch-the-following-discrete-time-signals-in-the-time-range-of-10-n

编辑： DGM 2023-11-4

n=-10:10;
u(1:21)=ones(1,21); %creates a unit step sequence for u(n)
                   %how to write a delayed version of sequence i.e for u(n-3) ?

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Aliya Patel 2018-11-23

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/243037-write-a-matlab-program-to-sketch-the-following-discrete-time-signals-in-the-time-range-of-10-n#answer_348530

编辑：DGM 2023-11-4

在 MATLAB Online 中打开

t = (-10:1:10)'; %%Can change the interval time by replacing 1 with 0.1

step1 = t>=0; %% For u[n]

step2 = t>=3; %%For u[n-3]

x = step1-step2;

plot(t,x) %%scatter can be used instead of plot

xlabel('time');

ylabel('amplitude');

title('x(n)=u(n)-u(n-3)');

2 个评论
显示无隐藏无

Satadru Mukherjee 2020-3-21

This is wrong , your code is not taking care of the time index :-/

DGM 2023-11-4

编辑：DGM 2023-11-4

Indexing looks fine, but representing this using plot() is visually misleading. I suspect that motivation is why Aliya suggested scatter(), though I think stem() would probably be better.

请先登录，再进行评论。

Answer 2

Satadru Mukherjee 2020-3-21

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/243037-write-a-matlab-program-to-sketch-the-following-discrete-time-signals-in-the-time-range-of-10-n#answer_421207

编辑：Satadru Mukherjee 2020-3-21

在 MATLAB Online 中打开

n1=-10:10;

x=(n1>=0);

n2=n1+3;

y=x;

u=min(min(n1),min(n2));

t=max(max(n1),max(n2));

r=u:1:t;

z1=[];

temp=1;

for i=1:length(r)

if(r(i)<min(n1) || r(i)>max(n1))

z1=[z1 0];

else

z1=[z1 x(temp)];

temp=temp+1;

end

z2=[];

temp=1;

for i=1:length(r)

if(r(i)<min(n2) || r(i)>max(n2))

z2=[z2 0];

else

z2=[z2 y(temp)];

temp=temp+1;

end

z=z1-z2;

subplot(3,1,1);

stem(r,z1);

xlabel('Time sample');

ylabel('Amplitude');

title('First signal');

subplot(3,1,2);

stem(r,z2);

xlabel('Time sample');

ylabel('Amplitude');

title('Second signal');

subplot(3,1,3);

stem(r,z);

xlabel('Time sample');

ylabel('Amplitude');

title('Signal after Subtraction');

3 个评论
显示 1更早的评论隐藏 1更早的评论

Walter Roberson 2020-5-16

It appends x(temp) to the end of z1. They wrote the code using that technique because people tend to learn the [] concatenation before they gain the experience to initialize an array to full size and write at a particular in the array.

Bhargav Jyoti Saikia 2021-3-27

Thank you very much. This program gave a clear idea as to how to implement these functions. Took little time to understand but after little debugging got the idea. There might be easier way or easier to understand simple method to achieve the same functionality.

请先登录，再进行评论。