plot summation of shifted discrete signals

Question

ayman daraghmah 2015-9-16

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https://ww2.mathworks.cn/matlabcentral/answers/243414-plot-summation-of-shifted-discrete-signals

评论： Nguyen Hong Son 2020-4-17

 n=-4:2;
 y=[1,-2,4,6,-5,8,10];
 n=n-2
 stem(n,y);

I want to plot Z = y(n-2)+y(n+1);

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Answer 1

Hamoon 2015-9-17

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https://ww2.mathworks.cn/matlabcentral/answers/243414-plot-summation-of-shifted-discrete-signals#answer_192764

编辑：Hamoon 2015-9-17

在 MATLAB Online 中打开

 n=-4:2;
 y=[1,-2,4,6,-5,8,10];
 maxShift = 10;                         % maximum shift that you may want,
                                        % you can't shift more than this value,
                                        % you should set this value high enough
                                        % I could set it to be 2 here, but I prefer 10 
 n=min(n)-maxShift:1:max(n)+maxShift;          % define proper range for n
 y=[zeros(1,maxShift), y, zeros(1,maxShift)];  % add zeros to the begining and
                                               % end of y 
 z= circshift(y',-2) + circshift(y',1);  % calculate your new signal. you need
                                         % transpose of y ==> y'

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Hamoon 2015-9-17

在 MATLAB Online 中打开

here is the output using:

subplot(2,1,1)
stem(n,y);
title('y')
axis([-15 15 -10 20])
subplot(2,1,2)
stem(n,z);
title('z')
axis([-15 15 -10 20])

Nguyen Hong Son 2020-4-17

Excuse me. Can I ask you why we can use circular shift to compute operations of shifted discrete signals? (I can't have the intuition or visualization of it)

Why do we need the transpose of y in the last line of code?

Thank you so much!

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