Unable to interpret fixed size array, matlab compiler

2015 9 17
1 个回答
更新时间：2015 9 17
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0 个投票

I have two lines of c++ code that I'm trying to interface through matlab. (1) does not work, but (2) works - why is that? I need to use (1).
(1)
typedef unsigned short uint16;
const uint16 kLevels = 256;
bool SetTable(const float (*newLut)[kLevels]);
(2)
enum
{
kLevels = 256;
};
bool SetTable(const float (*newLut)[kLevels]);
matlab calling routine:
table1 = zeros(1,256);
[flag] = calllib(libName,'SetTable', single(table1));
error is:
Error using loadlibrary (line xxx)
: error
C2057: expected constant expression
: error
C2466: cannot allocate an array of constant size 0
I have no problem using the uint16 in other places. Is the compiler not understanding this function definition?

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回答（1 个）

Walter Roberson
Walter Roberson 2015-9-17

0 个投票

You wrote
const unit16 kLevels = 256;
instead of
const uint16 kLevels = 256;

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NIKHIL
NIKHIL 2015-9-17
Sorry..that was a typo while asking the question. I have corrected the spelling mistake. The question still stands

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2015-9-17

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