Maxtrix copy and manipulation
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I have one matrix and one vector. I would like to shift the elements of row forward depending on the vector index.
M = [0 2 4 5;
0 4 7 9;
0 0 0 34];
v = [4 3 2];
Shift the elements of M forward, v(1) = 4 indicate start result with the 4th element of the row. Pad the end of row with zeros.
Result = [5 0 0 0;
7 9 0 0;
0 0 34 0]
How do I do this in the vectorized way?
Thanks, Fischer
采纳的回答
Star Strider
2015-9-17
This uses a loop, but I can’t see how to do this without one:
M = [0 2 4 5; 0 4 7 9; 0 0 0 34];
v = [4 3 2];
c = size(M,2);
Result = zeros(size(M));
for k1 = 1:size(M,1)
Result(k1,1:c-v(k1)+1) = M(k1,v(k1):c);
end
5 个评论
Fischer Zheng
2015-9-17
编辑：Fischer Zheng
2015-9-17
Stephen23
2015-9-17
MATLAB does not have a shift operator, let alone a vectorized version of it. You will have to create your own. While there could be solutions with cell arrays, cellfun, accumarray and the like, probably the fastest and least obfuscated solution would be to use a simple loop.
Star Strider
2015-9-17
I doubt if either ind2sub or accumarray or arrayfun or any of the others would work in this instance. Considering that you’re doing a different shift on each row, there is no way to vectorise this operation.
Fischer Zheng
2015-9-17
Star Strider
2015-9-17
Thank you.
If you’re doing this once for each large matrix, save the shifted matrix to a .mat file. Then you can simply load the shifted matrix when you need it, rather than recalculating it each time.
更多回答（1 个）
v=v(:);
[m,n]=size(M);
[I,J,S]=find(M);
J=J-v(I)+1;
idx=J>0;
Result=sparse(I(idx),J(idx),S(idx),m,n);
Result=full(Result); %optional
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