Binary to DNA sequence encoding - matlab
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I am implementing DNA encryption algorithm.
For that, I have a vector containing binary values such as:
01100011 01110010 01111001 01110000 01110100 01101111.
Now, these values should be mapped to DNA sequence. How do I do that in MATLAB?
2 个评论
Star Strider
2015-9-20
DNA has four bases (two complementary sets, A-T and C-G) and you have a binary sequence ...
Meghashree G
2015-9-20
采纳的回答
Image Analyst
2015-9-20
Perhaps this:
% Assign sample data.
binaryArray = [0,1,1,0,0,0,1,1, 0,1,1,1,0,0,1,0, 0,1,1,1,1,0,0,1, 0,1,1,1,0,0,0,0, 0,1,1,1,0,1,0,0, 0,1,1,0,1,1,1,1];
% Define base letters to choose from.
bases = 'ATGC';
for k = 1 : 2 : length(binaryArray)
% Convert these two digits into a number 1 - 4.
index = 2 * binaryArray(k) + binaryArray(k+1) + 1;
% Use that index to assign a letter to our result.
result((k+1)/2) = bases(index);
end
% Display in command window:
result
It shows:
result =
TGACTCAGTCGTTCAATCTATGCC
12 个评论
Meghashree G
2015-9-20
Saurabh Kumar
2018-2-12
I want to create a function in Matlab of above solution you have given. So that I don't need to describe different binary Everytime in .m blank file format. Please help Function []=binary()
Image Analyst
2018-2-12
function result = LabelBinaryArray(binaryArray)
% Define base letters to choose from.
bases = 'ATGC';
for k = 1 : 2 : length(binaryArray)
% Convert these two digits into a number 1 - 4.
index = 2 * binaryArray(k) + binaryArray(k+1) + 1;
% Use that index to assign a letter to our result.
result((k+1)/2) = bases(index);
end
Saurabh Kumar
2018-2-12
Attempted to access binaryArray(2); index out of bounds because numel(binaryArray)=1.
Error in LabelBinaryArray (line 6) index = 2 * binaryArray(k) + binaryArray(k+1) + 1;
NOT WORKING
Image Analyst
2018-2-12
It works if you pass in something like you said, like '01100011'. You can't pass in a single value like '1' like you did because that can't be mapped to a letter. How do I know you passed in only a single element? Because the error message says "because numel(binaryArray)=1" Are you sure you're passing in a binary array like you said? I'm assuming a binary array, which is class logical, though a double will work. You aren't passing in a string are you? Show me how you defined the array you passed in to the function.
Saurabh Kumar
2018-2-12
LabelBinaryArray('011000110111001001111001011100000111010001101111')
Attempted to access bases(146); index out of bounds because numel(bases)=4.
Error in LabelBinaryArray (line 8) result((k+1)/2) = bases(index);
Image Analyst
2018-2-12
OK, you have a string, not a binary/logical array. To convert to a binary array you need to do this:
str = '011000110111001001111001011100000111010001101111'
binaryArray = logical(str - '0')
You can do that either inside the function, if you want to pass a string, or in your main program before you call the function, if you want to pass a binary array.
Saurabh Kumar
2018-2-13
it worked. THANKS
Saravanakumar Chandrasekaran
2020-12-5
How to decrypt it back to binary sequence
Image Analyst
2020-12-5
Decrypt what back to a binary sequence. You have the binary sequence both as a character array, str, and a logical/boolean array, binaryArray. What else do you want? What's missing? Just keep both things and you're all set.
Shiva Reddy
2021-2-5
Pls Can I get the decryption code
Image Analyst
2021-2-5
Shiva, I'm not sure who you're asking, but personally I don't have any to give you.
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