How can I solve this odd/even loop question (hailstone sequence)?
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n = 71
If n is even, divide it by 2 to get n / 2.
If n is odd, multiply it by 3 and add 1 to obtain 3n + 1.
Repeat process until n = 1.
I need to find out how many steps it takes to reach 1..
thanks!
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Varun Pai
2015-9-22
I think this is your requiremnt. Please check
num = 71;
count = 0;
while(num~=1)
count = count+1;
if(mod(num,2)==0)
num = num/2;
else
num = 3*num + 1;
end
end
fprintf('count = %d', count);
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Thorsten
2015-9-22
First you can skip the 1, and just write n(ii).
Next you have forgotten to assign the new value, and you have to move the increment of ii outside the else-clause
if mod(n(ii),2)==1
n(ii+1) = 3*n(ii)+1;
else
n(ii+1) = n(ii)/2;
end
ii=ii+1;
Finally you have to change the while loop condition; while n(ii) == 1 means that the loops only continues if the n is 1, but it should continue if n is NOT 1.
另请参阅
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