Encoding Binary to DNA sequencing
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I am trying to convert the string into binary and sequencing with DNA,but i am getting error as follows :
Attempted to access bases(145); index out of bounds because numel(bases)=4.
Error in ==> filename at 21
result((k+1)/2) = bases(index);
What is the solution for this? Here is the code:
clc;
ui=input('enter the message:','s')
decString = unicode2native(ui,'utf-8')
hexString = dec2hex(decString)
binaryArray= dec2bin(decString,8)
bases = 'ATGC';
for k = 1 : 2 : length(binaryArray)
% Convert these two digits into a number 1 - 4.
index = 2 * binaryArray(k) + binaryArray(k+1) + 1;
% Use that index to assign a letter to our result.
result((k+1)/2) = bases(index);
end
% Display in command window:
result
Thank you
2 个评论
Shiva Reddy
2021-2-7
It is giving error like index exceeds (4)
Walter Roberson
2021-2-7
Yes, that is exactly the problem that was discussed in the Answer.
采纳的回答
Image Analyst
2015-9-25
0 个投票
bases has only 4 elements so index must stay in the range 1,2,3,4 not 145 like you have it. Think about the logic some more.
5 个评论
Walter Roberson
2015-9-25
编辑：Walter Roberson
2015-9-25
Remember your binaryArray is going to be something-by-8 but you are accessing it as if it is a vector. Also remember that the result of dec2bin() is characters not numeric so if you want numeric, subtract the character '0'
Meghashree G
2015-9-25
编辑：Walter Roberson
2015-9-25
Walter Roberson
2015-9-25
binaryArray = dec2bin(decString,8) - '0';
index = 2 * binaryArray(:,1:2:end) + binaryArray(:,2:2:end) + 1;
result = bases(index);
Meghashree G
2015-9-26
编辑：Walter Roberson
2015-9-26
Walter Roberson
2015-9-26
I do not see the difference between what you got and what you want.
To answer your question, though: No, it is not a vector, it is an array. Character strings in MATLAB are arrays, not individual entities. The "result" variable above is char of size 6 x 4
If you want it as a cell array of strings, then use cellstr(result)
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