MATLAB one-liners

One of the joys of using MATLAB is that it has a stock of matrix functions like diff, sort, all, and so on, that can be combined in all sorts of interesting ways. For example, in a recent question, the challenge was to find a compact code to determine which columns of a matrix A have all elements equal. Matt Tearle came up with this nifty answer:
all(~diff(A))
What are your favorite one-line MATLAB expressions?

 采纳的回答

cell2mat(arrayfun(@(K) accumarray(C, F(:,K), [], @mean), 1:size(F,2), 'Uniform', 0))
In response to a cssm question:
I have a feature matrix, F(m, n) and a cluster vector, C(m, 1).
Now I want to get the mean of feature in F according to C. Make
it simple as below:
F = [2 5; 3 7; 8 4]
C = [2; 1; 2]
output should be [3 7; (2+8)/2 (5+4)/2]
=[3 7; 5 4.5]

2 个评论

ARRAYFUN, and ACUMARRAY? About all that is missing is to somehow work BSXFUN in there too!
Even though BSXFUN is missing, I decided to accept this one. Very clever, @Walter!

请先登录,再进行评论。

更多回答(9 个)

I'm a huge fan of logical indexing. Expressions like
mean(frogs(wombats > 42))
rock my world.

3 个评论

Or how about mean(people(suck))?
I use the function 'keep' from the FEX which performs the inverse of clear.
I also use the variables 'in', 'out' a lot. So the other day I typed:
'keep out'
which kind of made my day.
I like it!

请先登录,再进行评论。

Here's another from a thread today:
Given a connected components analysis (bwconncomp) and some criteria for objects to meet: remove objects that don't meet that criteria from your binary image:
I(cell2mat(CC.PixelIdxList(~idx)')) = false;

1 个评论

idx can usually be a one line expression from cellfun making this a super-awesome-long-one-liner.

请先登录,再进行评论。

Matt Fig
Matt Fig 2011-3-3
Here is a good one. After already writing a solution to this Question, I stumbled upon this:
groups = mat2cell(A,diff([0;find(diff(A) ~= 1);length(A)]),1);
Pretty Slick.

6 个评论

Very nice, but Matt would be happier if you used logical indexing.
LOL, LI is tops, but not always necessary or useful.
Strange, I am sure I wrote code much like that in response to one of the numerous copies of that question. I cannot seem to find it now, though. I had the 1 first, and I used > instead of ~=
I had it stored in my "One liners" file, which is made up of one-liners either I or somebody else on CSSM wrote in response to some question. The file is too big to be much use anymore...
Matt Fig: "LI is tops, but not always necessary or useful"
An unbeliever! Persecute! Kill the heretic!
Ah, I found my copy, and it was _not_ a 1 liner. I had used
b=diff(a); %find differences
idx = find([b 2]>1); %find their indexes
cel = mat2cell(a, 1, [idx(1) diff(idx)]); %break up the matrix

请先登录,再进行评论。

Inspired by something I'm working on right now & your comment to my previous answer...
If you have an n-by-1 structure array people with a field suck (which contains a scalar for each struct element), and you want to find the average:
mean([people.suck])
Extract multiple elements, concatenate, apply function. All in one line.

1 个评论

I like compact expressions with social commentary.

请先登录,再进行评论。

Turn a structure array S into a cell array with the names of the fields in the first column:
C = horzcat(fieldnames(S), squeeze(struct2cell(S)))
Here is a real beauty from a comment by Tim Davis on a guest blog for Loren Shure. Suppose you have three 2D vectors p1, p2 and p3, and you want to know if they are collinear. The shortest solution also happens to be numerically the most reliable:
rank ([p2-p1 ; p3-p1]) < 2
It is also easily generalized to more dimensions!
eval('fliplr(['''' 33 33 33 33 33 76 105 118 69 32 109 39 73 ''''])')
MuAhahauHAh!!!

3 个评论

If you were really evil (or a quitter), you'd do
eval(char([113 117 105 116]))
You're the evilest!
I used to be an admin on a chess server where "qu" could be used as a shorthand to quit out of the interface. A common prank was to tell newbies that "qu" could be used to display the "quote of the day".

请先登录,再进行评论。

Here is an interesting way of calculating n rows of Pascal's triangle:
round(expm(diag(1:n-1,-1)))
Now if we could just remove the zeros and center it on the same line!

3 个评论

sprintf() it and regexrep() on the result, substituting spaces for leading space-zero-space; another regexprep() call could substitute spaces for trailing space-zero-space.
It's not pretty but just for fun, here's one way to do it:
trimmedTriangle = cell2mat(cellfun(@(x) x(1:size(num2str(expm(diag(1:n-1,-1))),2)),cellfun(@(x,y)[x y],cellfun(@(x) repmat(' ',1,x),num2cell(round(linspace(size(num2str(expm(diag(1:n-1,-1))),2)/2,0,n))'),'UniformOutput',false),regexprep(mat2cell(num2str(expm(diag(1:n-1,-1))),ones(n,1)),' 0',' '),'UniformOutput',false),'UniformOutput',false))
Wow! Three nested cellfuns! This deserves a separate answer.

请先登录,再进行评论。

Drew Weymouth
Drew Weymouth 2011-3-4

0 个投票

Read in an image and convert it to a grayscale, double matrix of data range 0..1
im= rgb2gray(double(imread('filename.jpg'))/255);

1 个评论

or more generally, rgb2gray(im2double(imread('filename.jpg')))
Your code would fail for images that happened to be already double or happened to be uint16.

请先登录,再进行评论。

类别

帮助中心File Exchange 中查找有关 Matrix Indexing 的更多信息

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by