If else condition for the rainfall
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I have series of daily rainfall data, computed curve number (CN). To compute runoff, I need to fulfill these two conditions
if Rainfall > 0.2
then Runoff = 1000/CN -10
else
Runoff =( Rainfall -0.2 * (1000/CN -10)^2)/Rainfall + 0.8 *(1000/CN -10)
Could any body suggest code for this? I tried to use following script
Runoff = ones(size(Rainfallinches));
>> idx = Rainfallinches >0.2;
>> Runoff(idx)= (1000* 1/Curvenumber -10);
but this doesnot work Kind regards, Saleem
[EDITED, Jan, copied from a new thread:]
My data is as follow Rainfall CN 8 65 2 66 6 88 8 73 5 63 4 65 6 66 5 88 1 73 2 63 3 65 5 66 1 88 5 73 10 63 4 65 3 66 3 88 4 73 3 63 I want to compute Runoff for the following conditions if Rainfall >10 then Runoff = 1000/CN-10 otherwise Runoff = (Rainfall - 0.2 * (1000/CN -10)^2)/Rainfall + 0.8 *(1000/CN -10) Please suggest me code for that kind of data.
3 个评论
Jan
2015-10-1
编辑:Jan
2015-10-1
Please do not open a new thread to provide data for an open question. This is too confusing for the readers.
If you post values, please use a form, which can be inserted in Matlab's command window by copy&paste. Only then it is clear to the readers. What are the size and type of the variables Rainfallinches and Curvenumber? And again: Please explain what "it does not work" mean. Give us a chance to help you.
回答(1 个)
Thorsten
2015-10-1
编辑:Thorsten
2015-10-1
You didn't mention what went wrong; the following code should work for you:
Rainfall = rand(1,10); % fake some data
CN = 23; % assume it is a scalar, fake some value
idx = Rainfall > 0.2;
Runoff(idx) = 1000/CN - 10;
Runoff(~idx) = (Rainfall - 0.2 * (1000/CN -10)^2)/Rainfall + 0.8 *(1000/CN -10);
2 个评论
Walter Roberson
2015-10-1
Runoff(~idx) = (Rainfall(~idx) - 0.2 * (1000/CN -10)^2)./Rainfall(~idx) + 0.8 *(1000/CN -10);
另请参阅
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