misbehave of find function

Question

Eng. Fredius Magige 2015-10-1

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/246296-misbehave-of-find-function

回答： Eng. Fredius Magige 2015-10-4

Within a certain row of adjacent (1,0 matrix) one of it point known(as is also 1), I use it as base and looking the next one as long has 1, if not, I have to start from the initial column within that row. Unfortunately not behaving as expected. Any suggestion is welcome. Thanks all, see the input (adjacency matrix, code and output of the behaving find function:

Input file:

CON=[0  1  0  0  0  0  0  0  0  0  0  0  0  0  0  1
1  0  1  0  0  0  0  0  0  0  0  0  0  0  0  0
0  1  0  1  0  0  0  0  0  0  0  0  0  0  0  0
0  0  1  0  1  0  0  0  0  0  0  0  1  0  1  0
0  0  0  1  0  1  0  0  0  0  0  0  0  0  1  0
0  0  0  0  1  0  1  0  0  0  0  0  0  1  0  0
0  0  0  0  0  1  0  1  0  0  0  0  0  1  0  1
0  0  0  0  0  0  1  0  1  0  0  0  0  1  0  0
0  0  0  0  0  0  0  1  0  1  0  0  0  0  1  0
0  0  0  0  0  0  0  0  1  0  1  0  1  0  0  0
0  0  0  0  0  0  0  0  0  1  0  1  0  0  0  0
0  0  0  0  0  0  0  0  0  0  1  0  1  0  0  0
0  0  0  1  0  0  0  0  0  1  0  1  0  0  0  0
0  0  0  0  0  1  1  1  0  0  0  0  0  0  1  0
0  0  0  1  1  0  0  0  1  0  0  0  0  1  0  0
1  0  0  0  0  0  1  0  0  0  0  0  0  0  0  0
];
[r c]=size(CON);
for n=1:size(CON,1)
    [rr cc]=find(CON(:,n)>0,n,'last');nn=n,rr,
    [pp p]=find(CON(rr,cc+1:c)>0,1)
    if(p>=1)
      [rrc rcc]=find(CON(rr,cc+1:end)>0,1),
    else
     [rrc rcc]=find(CON(rr,1:cc-1)>0,1),
    end
end

OUTPUT of find function (eg nn=2, pp=1, p=1; I meanwhile expectes p to be 2)

nn =1 rr = 16 
pp =1 p =   6
rrc =1 rcc =6
nn =2 rr = 3
pp =1  p=  1
rrc =1 rcc =1
nn =3 rr =  4
pp =1 p =   2
rrc =1 rcc =2
nn =4 rr = 15
pp =1 p =1
rrc =1 rcc =1
nn =5 rr =15
pp =1 p =2
rrc =1 rcc =2
nn = 6 rr =14
pp =1 p =3
rrc =1 rcc =3
nn =7 rr =16
pp = 1 p =4
rrc =1 rcc = 4
nn = 8 rr =14
pp =1 p =5
rrc =1 rcc =5
nn = 9 rr =15
pp =3 p =3
rrc =3 rcc =3
nn =10 rr =13
pp =3 p = 3
rrc =3 rcc = 3
nn = 11 rr = 12
pp = 1 p =8
rrc =1 rcc =  8
nn =12 rr =13
pp = 2 p = 3
rrc =2 rcc =3
nn =13 rr = 12
pp =1 p =2
rrc =1 rcc =2
nn =14  rr =15
pp =4 p = 3
rrc =4 rcc =3
nn = 15 rr =14
pp =1 p = 2
rrc =1 rcc =2
nn =16  rr =7
pp = 1 p = 1
rrc = 1  rcc =1

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Star Strider 2015-10-1

You need to post your data (or sample data), what you want as output, and the relevant parts of your code.

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Eng. Fredius Magige 2015-10-4

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/246296-misbehave-of-find-function#answer_194641

I succeed to resolve my question, "misbehaving of find function" I used and incorporate flipdim function in find (... last)function; I was endup with all previous related numerical figures; I have noted that adjacency matrix is not enough exploration in solving engineering networking challenges. Thanks Matlab team.