misbehave of find function
1 次查看(过去 30 天)
显示 更早的评论
Within a certain row of adjacent (1,0 matrix) one of it point known(as is also 1), I use it as base and looking the next one as long has 1, if not, I have to start from the initial column within that row. Unfortunately not behaving as expected. Any suggestion is welcome. Thanks all, see the input (adjacency matrix, code and output of the behaving find function:
Input file:
CON=[0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 1
1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0
0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0
0 0 1 0 1 0 0 0 0 0 0 0 1 0 1 0
0 0 0 1 0 1 0 0 0 0 0 0 0 0 1 0
0 0 0 0 1 0 1 0 0 0 0 0 0 1 0 0
0 0 0 0 0 1 0 1 0 0 0 0 0 1 0 1
0 0 0 0 0 0 1 0 1 0 0 0 0 1 0 0
0 0 0 0 0 0 0 1 0 1 0 0 0 0 1 0
0 0 0 0 0 0 0 0 1 0 1 0 1 0 0 0
0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0
0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0
0 0 0 1 0 0 0 0 0 1 0 1 0 0 0 0
0 0 0 0 0 1 1 1 0 0 0 0 0 0 1 0
0 0 0 1 1 0 0 0 1 0 0 0 0 1 0 0
1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0
];
[r c]=size(CON);
for n=1:size(CON,1)
[rr cc]=find(CON(:,n)>0,n,'last');nn=n,rr,
[pp p]=find(CON(rr,cc+1:c)>0,1)
if(p>=1)
[rrc rcc]=find(CON(rr,cc+1:end)>0,1),
else
[rrc rcc]=find(CON(rr,1:cc-1)>0,1),
end
end
OUTPUT of find function (eg nn=2, pp=1, p=1; I meanwhile expectes p to be 2)
nn =1 rr = 16
pp =1 p = 6
rrc =1 rcc =6
nn =2 rr = 3
pp =1 p= 1
rrc =1 rcc =1
nn =3 rr = 4
pp =1 p = 2
rrc =1 rcc =2
nn =4 rr = 15
pp =1 p =1
rrc =1 rcc =1
nn =5 rr =15
pp =1 p =2
rrc =1 rcc =2
nn = 6 rr =14
pp =1 p =3
rrc =1 rcc =3
nn =7 rr =16
pp = 1 p =4
rrc =1 rcc = 4
nn = 8 rr =14
pp =1 p =5
rrc =1 rcc =5
nn = 9 rr =15
pp =3 p =3
rrc =3 rcc =3
nn =10 rr =13
pp =3 p = 3
rrc =3 rcc = 3
nn = 11 rr = 12
pp = 1 p =8
rrc =1 rcc = 8
nn =12 rr =13
pp = 2 p = 3
rrc =2 rcc =3
nn =13 rr = 12
pp =1 p =2
rrc =1 rcc =2
nn =14 rr =15
pp =4 p = 3
rrc =4 rcc =3
nn = 15 rr =14
pp =1 p = 2
rrc =1 rcc =2
nn =16 rr =7
pp = 1 p = 1
rrc = 1 rcc =1
1 个评论
Star Strider
2015-10-1
You need to post your data (or sample data), what you want as output, and the relevant parts of your code.
采纳的回答
更多回答(0 个)
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!