How to plot a against varying phi value

2015 10 2
1 个回答
更新时间：2015 10 2
3 次查看（30 天）

0 个投票

I am sorry if this is an easy answer, I am a noob on this.
del=sin(beta)^2(1+s^2+I)-sin(phi)(sin(phi)+u*cos(phi))
tan(beta)=1/s
s=0.95,1.0,1.1,1.2
u=0.75
I=1
I have to plot del against phi
Phi should go from 0 degrees to 90 degrees
How do I go about doing this ?
Thanks in advance.

请先登录，再回答此问题。

回答（1 个）

Andrei Bobrov
Andrei Bobrov 2015-10-2
编辑：Andrei Bobrov 2015-10-2

0 个投票

phi = (0:90)';
s = [0.95,1.0,1.1,1.2];
sd = sind(phi);
plot(phi,bsxfun(@minus,sin(1./s).^2.*(1+s.^2+1),sd.*(sd+.75*cosd(phi)));

类别

在 帮助中心 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by