The code below explains program to evaluate a 2x2 rotation matrix for given input angle.The code seems to be fine for all elements but one in1st row and second column.Can't figure out where I'm wrong.

3 次查看(过去 30 天)
function [ var ] = rot( theta )
for j=1:2,
for i=j:2,
if (i==j)
var(i,j) = cosd(theta);
elseif (i-j>0)
var(i,j) = sind(theta);
else
var(i,j) = -sind(theta);
end
end
end
var;
end
The problem, is with var(1,2) which always displays a zero irrespective of angle value.

采纳的回答

Stephen23
Stephen23 2015-10-3
编辑:Stephen23 2015-10-3
Using loops is very inefficient code. Try this instead:
function mat = rotmat2d(theta)
assert(isnumeric(theta)&&isscalar(theta),'Value must be a scalar numeric')
mat = [cosd(theta),sind(theta);-sind(theta),cosd(theta)];
end
and tested:
>> rotmat2d(0)
ans =
1 0
0 1
>> rotmat2d(90)
ans =
0 1
-1 0
>> rotmat2d(45)
ans =
0.70711 0.70711
-0.70711 0.70711
>> rotmat2d(180)
ans =
-1 0
0 -1
  2 个评论
Jai  Khullar
Jai Khullar 2015-10-3
Seems I was taking the hard way. Is there really a need of assert command? please do answer this one! I'm new in matlab. Anyways it was helpful. Thanks!
Stephen23
Stephen23 2015-10-3
编辑:Stephen23 2015-10-3
The assert command fits into the category of "your function will work without it, but it is highly highly recommended". Using assert and checking input arguments is certainly a good habit to get into. The trick is to make the checking as minimal as possible, to allow your function to be a general as possible.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Graphics 的更多信息

标签

尚未输入任何标签。

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by