I actually wrote a function to do some of that just for the fun of it yesterday.
engstr = @(x) [x*10.^(-3*floor(log10(abs(x))/3)) 3*floor(log10(abs(x))/3)];
z = 1.6755e+05;
Result = engstr(z)
Result =
167.5500 3.0000
The ‘engstr’ function produces a (1x2) vector, the first element is the engineering notation mantissa, and the second is the exponent. Just use the first element to get the result you want.
