Averaging multiple cells element by element

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I have 7 cells (named 'npsoutOrg1'...'npsoutOrg7'), each with a dimension of 5*1 cells. I want to take the average of each position across all 7 cells element by element and have the input stored in a 5*1 cell named 'npsoutOrgaverage'. How do I do that?
I tried first adding element by element with cell fun, but it would only allow 2 cells to be added at one time.
npsoutOrgAVG{1}=cellfun(@plus,npsoutOrg1{1},npsoutOrg2{1},'Un',0);
instead of
npsoutOrgAVG{1}=cellfun(@plus,npsoutOrg1{1},npsoutOrg2{1},...npsoutOrg7{1},'Un',0);
Plus, if this works, I still have to do it individuall for npsOutOrgAvg{2}... to npsOutOrgAvg{5}. Is there a faster way to average elements in the same position of the cells?
Not sure if this is of importance, but here's what each cell looks like:
%ROI 7: (207:267,23:83)
npsoutOrg7=cell(5,1);
for i = 39:141
[nps,f,nps2,fx,fy] = nps2d(im{i}(207:267,23:83),0.7813);
npsoutOrg7{1}{end+1} = nps;
npsoutOrg7{2}{end+1} = f;
npsoutOrg7{3}{end+1} = nps2;
npsoutOrg7{4}{end+1} = fx;
npsoutOrg7{5}{end+1} = fy;
end
Thanks so much!
  5 个评论
Brian
Brian 2015-10-6
I think I am getting the basic idea of what you mean by 3D array - so instead of having npsoutOrg1 to npsoutOrg7, there should just be one variable npsoutOrg? How would I actually carry it out? The tricky part is that each computation is based on a different set of coordinates...
Stephen23
Stephen23 2015-10-6
How to carry it out: use an internet search engine to research these topics:
  • Matrix indexing
  • Code vectorization
  • Array preallocation
  • Array indexing or multidimensional indexing

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回答(1 个)

Joseph Cheng
Joseph Cheng 2015-10-6
编辑:Joseph Cheng 2015-10-6
% my code to create dummy data
x = randi(10,5,7);
npsoutOrgN = mat2cell(x,5,ones(1,7));
%put all into an array
%npsoutOrgN = [npsoutOrg1 npsoutOrg2 .... npsoutOrg3];
npsSum = zeros(5,1);
for ind = 1:7
npsSum = npsSum +npsoutOrgN{ind};
end
npsAve= npsSum/7
or... bypass the for loop and convert npsoutOrgN into an array and use mean()
  2 个评论
Brian
Brian 2015-10-6
Thanks for the comment, but I am still getting "Undefined function 'plus' for input arguments of type 'cell'." I think this is because my data is a cell within a cell?
Joseph Cheng
Joseph Cheng 2015-10-7
does your data look like ex in the dummy code below?
for ind = 1:5
for jind = 1:5
ex{ind,jind} = {randi(10,1,2)};
end
end

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