清空筛选条件
清空筛选条件

Variable change over time

6 次查看（过去 30 天）
Amaral
Amaral 2015-10-8
评论： Star Strider 2015-10-9
Hello friends!
I have three 2d points (the xx values represents time instants between [0;1] and yy represents rotation values): initial = [0 , 0]; middle = [0.5 , 1.5409]; final = [1 , 3.0817];
I'm looking to do an interpolation of the remaining points for each 0.1 in the xx axis. The easiest way is to do a linear interpolation using linspace, but in this case i dont want to use evenly spaced values. What i want to do have is to have lower yy values on the first 4 intervals ([0 ; 0.4]) and higher yy values on the last 4 ([0.6 ; 1]), like the one i represented on the image below with orange color (blue represents the linear interpolation). Any ideas? Thanks for helping! :)

请先登录，再回答此问题。

采纳的回答

Star Strider
Star Strider 2015-10-8
I would fit it with a Logistic function, simply because it looks like one.
  4 个评论
显示 2更早的评论
Amaral
Amaral 2015-10-9
Yes it is! Thanks a lot friend! :)

请先登录，再进行评论。

更多回答（1 个）

Robert Dylans
Robert Dylans 2015-10-8
编辑：Robert Dylans 2015-10-8
If there's no particular requirement for the function's data, other than it "looks like" that kind of shape, you can use a formula similar to this:
x=0:0.01:1;
y=3.0817*(1-(1-((2*x).^3)./8).^5);
plot(x,y)
This was just a formula I happened to be using for something else, that has a similar curve fit. I'm sure there are many with similar functions. Note that this one only works for values of x in the range of [0 1]

类别

在 Help Center 和 File Exchange 中查找有关 Interpolation 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by