How to repeat a random number generation and simulation for 1000 times

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Hanson Zhou
Hanson Zhou 2015-10-14
回答： Guillaume 2015-10-14
Hi all, I have a code for random number generation and simulation for queuing experiment. The code is as below
code:
time=6;
lambda=5;
mean_arr=1/lambda;
num_arr=time*lambda*5;
interval=exprnd(mean_arr,1,num_arr);
intv(1,:)=interval;
arr_time(1,:)=cumsum(intv(1,:));
num_vaild=sum(arr_time(1,:)<=time);
data(1,:)=arr_time(1:num_vaild);
mean_treat=1/4;
std_treat=1/6;
data(2,:)=normrnd(mean_treat,std_treat,1,num_vaild);
for j=1:num_vaild
if data(2,j)<0
data(2,j)=0;
end
end
data(3,1)=0;
data(4,1)=data(1,1)+data(2,1);
patient=[1];
for i=2:num_vaild
queue=sum(data(4,patient)>data(1,i));
if queue==0;
data(3,i)=0;
data(4,i)=data(1,i)+data(2,i);
patient=[patient,i];
else num_patient=length(patient);
data(3,i)=data(4,num_patient)-data(1,i);
data(4,i)=data(4,num_patient)+data(2,i);
patient=[patient,i];
end
end
doctor_leavingtime = data(4,num_vaild);
I need to repeat this entire script for 1000 times and record the doctor's leaving time in data(4,end) every time, and create a vector for them.
any idea about how to repeat?

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回答（1 个）

Guillaume
Guillaume 2015-10-14
doctor_leavingtime = zeros(1, 1000);
for repeat = 1:1000
%your code to repeat
%...
doctor_leavingtime(repeat) = data(4, num_valid);
end
Unless I misunderstood your question that's all you have to do: wrap your original code in a loop.

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