Although it might seem most natural to code sum(w)=1 as a linear equality constraint, that form is inefficient because it can take a lot of hunting to fit the equality. Instead use one fewer w, calculate the last w(i) as 1 minus sum(w(1:i-1)), and have a linear inequality constraint on sum(1:i-1) as being < 1 (strictly) so that there always some room for the last w(i)
Double summation with multiplication
7 次查看(过去 30 天)
显示 更早的评论
Hi there, I currently working on a my study's final project One of which require me to solve this kind of equation
Objective is to maximize this function

r, sigma(i) --> for standard deviation, teta, and cov(i,j) are known number and I want to find the w(i) value with constraint: - Lower bound for w(i) is 0 - Upper bound for w(i) is 0 - Sum w(i) is 1
Any help is very appreciated and sorry for bad english
0 个评论
回答(1 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!