Number Of Frames in Video File with Matlab 2015b

22 次查看（过去 30 天）
albayenes
albayenes 2015-10-21
评论： Walter Roberson 2021-3-17
Hi,
In Matlab 2015b, NumberOfFrames property of VideoReader is deprecated. So, what is the best way to learn number of frames in a video?
  1 个评论
Cristina Vasco
Cristina Vasco 2016-7-18
When I use NumberOfFrames in a script, there's some hover-over advice to "use 'CurrentTime' instead." This is not particularly helpful and seems wrong. Could someone update this help?

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Dinesh Iyer
Dinesh Iyer 2015-10-21
The NumberOfFrames property is on the path to deprecation but querying this property still works. This deprecation indicates that this might be removed in some future release. This was first announced in 14b but has not been removed for the past three releases.
If this property is infact removed, then there are two ways to determine this.
First way is to compute it using the formula:
vidObj = VideoReader('myfile.mp4');
numFrames = ceil(vidObj.FrameRate*vidObj.Duration);
This formula above gives only an "estimate" of the number of frames. For fixed frame-rate files, the value will be within 1 of the actual number of frames due to rounding issues. Many video files are variable frame-rate and so for those files the actual number of frames can be more or less than the estimated value.
To get the exact value, you have no choice but to scan through the entire file using the code below:
vidObj = VideoReader('myfile.mp4');
numFrames = 0;
while hasFrame(vidObj)
readFrame(vidObj);
numFrames = numFrames + 1;
end
If your application requires knowledge of exact number of frames use the second method. If you want to know this value for pre-allocating arrays use the first method.
Hope this helps.
Dinesh
  7 个评论
显示 5更早的评论
Billy Pilgrim
Billy Pilgrim 2021-3-3
Hi Dinesh,
Thanks for your answer above. I've been using the 'while hasFrame' approach for a while now for getting exact frame numbers.
I was wondering if you had any approaches that might expedite the process? Preallocating isn't a thing in this case because numFrames is just a single value, not an array we're adding to? Similarly, there's no way to read a subset of the frame rather than the entire frame, correct? Just wondering if you had any ideas of tricks for speeding things up...
Walter Roberson
Walter Roberson 2021-3-17
You could potentially estimate the number of frames, then subtract a bit in case of estimation error, and then use the read() method instead of readFrame() to position to a particular frame number, and then readFrame from there to find the actual last frame.
However, it is not clear that read() with a frame number is efficient: it might have to read all of the frames in order to count them.
What is efficient is positioning by time. But positioning by time does not give you a frame count.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Audio and Video Data 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by