Can I use if ..break...else inside the same loop?

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Bee 2015-10-21

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https://ww2.mathworks.cn/matlabcentral/answers/250213-can-i-use-if-break-else-inside-the-same-loop

编辑： Bee 2015-10-26

My apology if it seems very trivial to all, but I have looked into the answers and could not find one single example which used if..break...else in the same loop. In my code, I want the value of t, where any of the variables x(t) or y(t) or z(t).... equals M (some pre set value) for the first time and then discontinue the iteration; otherwise it will return 0. So my code snippet looks like:

for i = 1:T
  ...
  ...
  if x(t) == M || y(t) == M || z(t) == M || a(t) == M || b(t) == M
    target = t;
    break
  else
    target = 0;
  end
end

I got some suspicious answers, so I was thinking whether the problem is in the use of break or the random probabilities I used in my code. Thanks.

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per isakson 2015-10-21

编辑：per isakson 2015-10-21

The use of break looks ok!
"I got some suspicious answers". How come "suspicious" ?

Bee 2015-10-22

编辑：Bee 2015-10-22

Dear _ _per isakson,__thanks for your comments. The word 'suspicious' has a story - I was looking into the occurrence of consensus in a scale-free network and got some reasonable points of consensus; but after some tweaks here and there to change the simulation scenario, I am getting consensus even with a large population having varying opinions - this is 'suspicious' to me, because reaching consensus in a large network is fairly impossible.

However, I am happy that I used if..break..else correctly, so the 'suspicious' results must have something to do with the probabilities of opinion updates or network structure.

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Answer 1

Robert 2015-10-21

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https://ww2.mathworks.cn/matlabcentral/answers/250213-can-i-use-if-break-else-inside-the-same-loop#answer_196912

编辑：Robert 2015-10-22

Your code looks fine. However, you can simplify the structure by adding target = 0; before your loop and omitting the else statement.

You might also consider using find(X==M,1), replacing X with each of your variables and then using min to find the index of the first occurrence of M, equivalent to your iterator i when you hit the break statement.

In any case, your use of if...break...else is not incorrect.