Shuffling elements within the rows of a matrix

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Say I have a matrix, I would like to shuffle the elements within the rows randomly. For example,
A = randi(1000, 3,4)
A =
815 279 958 793
906 547 486 960
127 958 801 656
I need to get the shuffled matrix like this
B =
279 793 958 815
960 547 486 906
801 127 958 656
The most straightforward way I can think of achieving this is to use randperm to shuffle the indices of each row, and then loop over the number of rows to create the shuffled matrix. But I would like to get it all done in one go, preferably more elegantly than using a loop, because I need to do this for large matrices many times. So, alternatively, I tried this:
[nr,nc] = size(A);
P=perms(1:nc);
col_indx_mtrx = P(randi(size(P,1),nr,1),:);
ri = repmat((1:nr)',1,nc);
which gives me
ri =
1 1 1 1
2 2 2 2
3 3 3 3
col_indx_mtrx =
2 1 4 3
3 4 1 2
1 4 2 3
Now, after this, I thought if I simply do
B = A(ri,col_indx_mtrx)
I am done. But, I don't get the desired result, because when I give the row and column indices as matrices, MATLAB tries to create a matrix with all combinations of the row and column indices?
Essentially, what I need is to create the shuffled matrix B such that
B(1,1) = A(ri(1,1), col_indx_mtrx(1,1))
and so on. Is there an elegant way to achieve this last step? I tried to use arrayfun, but I could not get it done.
Or, better, is there a more elegant way of achieving the overall objective?
Any help would be greatly appreciated.

采纳的回答

the cyclist
the cyclist 2015-10-24
Here's one way:
% Original matrix
A = randi(1000, 3,4);
[M,N] = size(A);
% Preserve the row indices
rowIndex = repmat((1:M)',[1 N]);
% Get randomized column indices by sorting a second random array
[~,randomizedColIndex] = sort(rand(M,N),2);
% Need to use linear indexing to create B
newLinearIndex = sub2ind([M,N],rowIndex,randomizedColIndex);
B = A(newLinearIndex);
  3 个评论
Sahil Bansal
Sahil Bansal 2017-4-30
编辑:Sahil Bansal 2017-4-30
And how can I shuffle the elements in the column randomly?
Jan
Jan 2017-4-30
编辑:Jan 2017-4-30
Sorting random indices is less efficient and has a tiny bias compared to the stable Fisher Yates shuffle: There is (and must be) the chance, that rand(1, 2) replies two equal numbers. Matlab's sort is stable, such that the first occurrence is preferred.
In older Matlab versions randperm used the sorting of random vectors also, but now the relation between data size and runtime looks like the faster Fisher Yates shuffle is used also, when it is called with 2 inputs:
tic;
v = randperm(1e6);
toc;
tic;
v = randperm(1e6, 1e6);
toc;
Elapsed time is 0.204787 seconds.
Elapsed time is 0.086091 seconds.
I've delivered a suggestion for improvements.

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更多回答(3 个)

Matt J
Matt J 2015-10-24
编辑:Matt J 2015-10-26
[m,n]=size(A);
T=perms(1:n); %tabulate once only
J=T(randi(m,m,1),:);
B=A( bsxfun(@plus,(1:m).', (J-1)*m) );

Thorsten
Thorsten 2015-10-26
编辑:Thorsten 2015-10-26
To achieve the last step in your code, use sub2ind:
B = A(sub2ind([nr nc], ri, col_indx_mtrx));

Jan
Jan 2017-4-30
A = randi(1000, 3,4);
A1 = Shuffle(A, 1);
A2 = Shuffle(A, 2);

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